program obr;
uses crt;
var a,b,i: byte;
begin
clrscr;
write('введите а: ');
readln(a);
write('введите b: ');
readln(b);
for i: =b downto a do
writeln(i: 2);
readkey;
end.
1)
var
a, b, s : real;
begin
read (a, b);
s : = a * b;
write (s: 10: 4);
end.
2)
var
a, b, c, k : integer;
begin
read (a, b, c);
k : = 0;
if a > 0 then inc (k);
if b > 0 then inc (k);
if c > 0 then inc (k);
writeln (k);
end.
3)
var
a : integer;
begin
read (a);
writeln ((a mod 10) * (a mod 100 div 10) * (a div 100 mod 10) * (a div 1000));
end.
4)
var
c, n : integer;
begin
read (n);
c : = 0;
repeat
inc (c);
n : = n div 10;
until n = 0;
writeln (c);
end.
5)
var
n, sum, i : integer;
begin
read (n);
sum : = 0;
for i : = 1 to n do
sum : = sum + i;
writeln (sum);
end.
6)
var
d, n, k : integer;
begin
read (n, k);
d : = 0;
while n > = k do
begin
d : = d + 1;
n : = n - k;
end;
writeln ('n div k = ', d);
writeln ('n mod k = ', n);
end.
7)
var
n, sum, i, tmp : integer;
begin
read (n);
sum : = 0;
for i : = 1 to n do
begin
read (tmp);
sum : = sum + tmp;
end;
writeln (sum / n);
end.
8)
var
i, n, s : integer;
a : array [1..1000] of integer;
begin
s : = 2;
read (n);
for i : = 1 to n do
begin
a[i] : = s;
s : = s + 2 * i + 1;
end;
for i : = 1 to n do write (a[i], ' ');
end.
9)
var
n, i, count, tmp : integer;
begin
read (n);
count : = 0;
for i : = 1 to n do
begin
read (tmp);
if tmp < 0 then inc (count);
end;
writeln (count);
end.
10)
var
n, i, j : integer;
begin
read (n);
for i : = 1 to n do
begin
for j : = 1 to i do
write ('*');
writeln;
end;
end.
11) //не понял, как заполняется массив? тут рандом
var
a : array [1..1000] of integer;
i, n : integer;
begin
read (n);
for i : = 1 to n do
a[i] : = trunc (random (1000)) - 500;
for i : = 1 to n do
if a[i] > 0 then a[i] : = a[i] * (-1)
else if a[i] < 0 then a[i] : = sqr (a[i]);
for i : = 1 to n do
write (a[i], ' ');
end.
12)
var
n, i, count : integer;
begin
read (n);
count : = 0;
for i : = 1 to n do
if n mod i = 0 then inc (count);
writeln (count);
end.
Поделитесь своими знаниями, ответьте на вопрос:
Сколько мегабайт информации содержит сообщение объемом 2^23 степени бит? объясните, , как решать такие ?