ответ:
m(na₂o)=620г.
объяснение:
дано:
m(naoh)=800г.
m(na₂o)-?
решение:
1. определим молярную массу гидроксида натрия:
m(naoh)=23+16+1=40г./моль
2. определим количество вещества гидроксида натрия в 800г.:
n₁(naoh)=m(naoh)÷m(naoh)=800г.÷40г./моль=20моль
3. запишем уравнение реакции:
na₂o+h₂o=2naoh
а) по уравнению реакции количество вещества:
n(naoh)=2моль n(na₂o)=1моль
б) по условию количество вещества :
n₁(naoh)=20моль n₁(na₂o)=10моль
4. определим молярную массу оксида натрия:
m(na₂o)=2x23+16=46+16=62г./моль
5. определим массу оксида натрия количеством вещества 10моль :
m(na₂o)=n₁(na₂o)×m(na₂o)=10моль×62г./моль=620г.
6. ответ: если образовалось 800г. гидроксида натрия то в воде растворилось 620г. оксида натрия.
ответ:
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Бутан + в сказано, что образуется три монохлорпроизводных, но у меня получается пять. прошу . напишите, , все монохлорпроизводные.