Осуществить цепочку превращений: cu-cuso4-(cuoh)2so4-cu(oh)-cu(hso4)2-cuso4

cu + h2so4 = cuso4 + h2

cuso4 + h2o = (cuoh)2so4

формула w = (n*ar) / mr   * 100%

в каждом действии я не стала писать умножение на 100%.  

h2s:

w(h) = 2 * 1 / 34 = 5,88%

w(s) = 1*32 / 34 = 94,1%

 

nh4cl:

w(n) = 1 * 14 / 53,5 = 26,2%w(h) = 4 * 1 / 53,5 = 7,5%

w(cl) = 1 * 35,5 / 53,5 = 66,4%

 

ca(h2po4)2:

w(ca) = 1*40 / 234 = 17%

w(h) = 4*1 / 234 = 1,7%

w(p) = 2 * 31 / 234 = 26,5%

w(o) = 8*16 / 234 = 54,7%

 

cacl2:

w(ca) = 1*40 / 111 = 36%

w(cl) = 2*35,5 / 111 = 64%

 

cu2co3(oh)2

w(cu) = 2*64 / 222 = 57,65%

w(c) = 1*12 / 222 = 5,4%

w(o) = 3+2 * 16 / 222 = 36%

w(h) = 2 * 1 / 222 = 0,9%

 

h2so4:

w(h)= 2*1 / 98 = 2,04%

w(s) = 1*32 / 98 = 32,65%

w(o) = 4*16 / 98 = 65.3%

 

 

h2s:

m(h2s)=34

w(h) = 2•1 / 34 = 5,88%

w(s) = 1•32 / 34 = 94,1%

 

nh4cl:

m(nh4cl)=53,5

w(n) = 1•14 / 53,5 = 26,2%w(h) = 4•1 / 53,5 = 7,5%

w(cl) = 1•35,5 / 53,5 = 66,4%

 

ca(h2po4)2:

m(ca(h2po4)2)=234

w(ca) = 1•40 / 234 = 17%

w(h) = 4•1 / 234 = 1,7%

w(p) = 2•31 / 234 = 26,5%

w(o) = 8•16 / 234 = 54,7%

 

cacl2:

м(cacl2)=111

w(ca) = 1•40 / 111 = 36%

w(cl) = 2•35,5 / 111 = 64%

 

cu2co3(oh)2:

м(cu2co3(oh)2)=222

w(cu) = 2•64 / 222 = 57,65%

w(c) = 1•12 / 222 = 5,4%

w(o) = 3+2•16 / 222 = 36%

w(h) = 2•1 / 222 = 0,9%

 

h2so4:

m(h2so4)=98

w(h)= 2•1 / 98 = 2,04%

w(s) = 1•32 / 98 = 32,65%

w(o) = 4•16 / 98 = 65.3%

 

 

ах..да..еще нужно нужно умножать на 100%..