Начертите прямоугольник у которого длина 5 см а ширина на 2 см короче, чем длина. найдите периметр и площадь прямоугольника

1:18см, 4см

2:16см, 6см

P1=18+18+4+4=44

P2=16+16+6+6=44

P1=(18×2)+(4×2)=44

P2=(16×2)+(6×2)=44

Пошаговое объяснение:

Мы знаем длина второго меньше первого значит 1A>2A как минимум на 1 18>1 в принципе можно почти любую цифру но что бы не парится я взял число кратное двум, это 16 берём изначальную ширину и прибавляем то что взяли у длины то есть 2 выйдет 6,вспоминаем что у прямоугольника 2 ширины и 2 длины и через них считаем периметр. Формула периметра p=A+A+B+B= или p=(A×2)+(B×2)= это основные формулы периметра.

Допольнительно:

Периметр: P

Длина: A

Ширина: B

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