Изобразите множество всех точек м(х; у) координатной плоскости оху, для каждой из которых(х2+у-8)/х+1=0

расстояние от точ. M до пр

Объяснение:

https://www.bch.org.au/network/members/profile?UserKey=65a868ee-40b7-48e6-8f16-a1ae7bd4a5ed

https://www.bch.org.au/network/members/profile?UserKey=5314a60e-fcce-4a8e-9dfe-e54c62466070

https://www.bch.org.au/network/members/profile?UserKey=2e5e1d37-06fa-4a2f-add3-064ccdba2cd7

https://www.bch.org.au/network/members/profile?UserKey=1cab6cba-9687-4402-8017-11c47a981db1

https://www.bch.org.au/network/members/profile?UserKey=50c7750b-25da-42bb-9f06-8995852de311

https://www.bch.org.au/network/members/profile?UserKey=c9137f64-f115-4856-b16e-725324070eba

https://www.bch.org.au/network/members/profile?UserKey=ddc4bb0b-e81b-4f0a-aa18-3e1a7c0aad8e

https://www.bch.org.au/network/members/profile?UserKey=46ecf1f9-b873-4366-a05e-5e9bf7a99c82

https://www.bch.org.au/network/members/profile?UserKey=0ae61c07-9e3f-4322-bdf0-5c1dfc8e3439

https://www.bch.org.au/network/members/profile?UserKey=9dcf19d1-f5f5-4ee2-9d81-e1da92198d59

https://www.bch.org.au/network/members/profile?UserKey=f43c2f8d-3eb1-4628-b429-20de9870d8c8

https://www.bch.org.au/network/members/profile?UserKey=eb967fac-02a2-4243-bffc-4c903e7b6acb

https://dcm.shivtr.com/forum_threads/3430850

https://caribbeanfever.com/profiles/blogs/the-frankish-merovingian-kings

https://paiza.io/projects/79qrAGtZkX8KiL4P0Do0zA?language=php

https://caribbeanfever.com/events/the-pandemic-occurred-national-protests

https://caribbeanfever.com/profiles/status/show?id=2663233%3AStatus%3A12708661

4mark.net/story/3697493/hd-virus-shark-(2021)-download-full-movies-profile-bellarine-community-health

http://www.4mark.net/story/3697528/hd-wrath-of-man-(2021)-download-full-movies-profile-bellarine-community-health

https://indexbacklink.cookpad-blog.jp/articles/604020

https://indexbacklink.cookpad-blog.jp/articles/604022

https://m.mydigoo.com/forums-topicdetail-274594.html

https://m.mydigoo.com/forums-topicdetail-274596.html

https://m.mydigoo.com/forums-topicdetail-274598.html4598.html

ответ:  29,6  км/час.

Объяснение:

"Катер проходит 160 км по течению реки за то же время, что и 136 км — против течения. Найдите собственную Скорость катера, если скорость течения реки равна 2,4 км/ч.​"

***

Собственная скорость катера х км /час.

По течению  --  х+2,4 км/час.

Против течения  --  х-2,4 км  /час

Время в пути    по течению    t1=s/v=160/(x+2.4)  часов.

Время в пути против течения   ---   t2=s/v=136/(x-2.4)  часов.

---

t1=t2;  

160/(x+2.4)= 136/(x-2.4);

160(x-2.4)=136(x+2.4);

160x-384=136x+326.4;

160x-136x=326.4+384;

24x=710.4;

x=29.6  км /час.