Одз {x-1> 0⇒x> 1 {x²-8x+6≥0 d=64-24=40 x1=4-√10 u xx2=4+√10⇒x≤4-√10 u x≥4+√10 {x²-4x+3≤0 x1+x2=4 u x1*x2=3⇒x1=1 u x2=3⇒1≤x≤ 3 \\\\\\\\\\\\\\\\\\ \\\\\\\\\\\\ \\\\\\\\\\\\\\\\\\\\\\\\\\\\\ -√+√ \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\ общего решения нет
agutty3
11.05.2022
Одз {x-1> 0⇒x> 1 {x²-8x+6≥0 d=64-24=40 x1=4-√10 u xx2=4+√10⇒x≤4-√10 u x≥4+√10{x²-4x+3≤0 x1+x2=4 u x1*x2=3⇒x1=1 u x2=3⇒1≤x≤ 3 \\\\\\\\\\\\\\\\\\ \\\\\\\\\\\\ \\\\\\\\\\\\\\\\\\\\\\\\\\\\\ \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\ -√+√