Найдите число отрицательных членов арифметической прогрессии -41; -36; -

Ответ: 9 отрицательных членов

10-4(2x+5)=6y-13

4y-63=5(4x-2y)+2

 

4y-63=5(4x-2y)+2

4y-63-20x+10y-2=0

14y-65-20x=0

x=0.7y-3.25

 

10-4(2x+5)=6y-13

3-8x-6y=0

3-8*(0.7y-3.25)-6y=0

3-5.6y+26-6y=0

29-11.6y=0

y=29/11.6y=2.пятых

 

14y-65-20x=0

14*2.5-65-20x=0

-30-20x=0

x=-30/20

x=-1.5

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{x> 0; x≠1 {log(2)x +2*(1/log(2) x)< 3log(2)x 1)log(2)x≠0;   ( log(2)x)^2+2< 3;   log(2) x> 0                   log^2 (2)x-3log(2)x +2 < 0                   y=log(2)x; y^2-3y+2< 0; d=9-8=1; y1=(3-1)/2=1; y2=2                   +                     -                 + > y                                 ////////////////////       1< log(2)x< 2; log(2)2< log(2)x< log(2)4 2< x< 4 2)log(2)x< 0;   log^2(2)x+2> 3log(2)x; log^2(2)x-3log(2)x+2> 0;   log(2)x⊂(0; 1)∪(2; +∞)   ;         0< log(2)x< 1; x⊂   (1; 2)       ili   2< log(2)x< +∞;   x⊂(4; +∞) (смотрим по графику! ) x⊂(1; 2)∪(2; 4)∩(4+∞)-это ответ.