kenni19868
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Дана квадратичная функция f(x)=x^+2.найдите значения: 1)f(4); 2)f(-3); 3)f(-1\2); 4)f(-0.2)^.решите

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Ответы

Norov

(4) = 18f(-3) = 11f(-1/2) = 2,25f(-0.2) = 2,04

подставь вместо икс число и выполни действие. например,  f(4)=4в квадрате+2=18. 

a8227775

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Must Waste More Time...

rigina82

Объяснение:

1) Квадратичная функция имеет вид ах² + bx + c, поэтому подходит ответ под буквой а) y = 3x - x²

2) Нулями функции называются такие значения х, при которых значение функции (т. е. y) равно нулю

а) у = х² - 6х + 8 = 0

Решим квадратное уравнение через дискриминант.

x = 2

x = 4

Это и есть нули функции

б) y = 2x² + 6x

Вынесем общий множитель 2х

2х(х + 6) = 0

Произведение равно нулю, когда хотя бы один из множителей равен нулю.

2х = 0

х + 6 = 0

х = 0

х = -6

в) у = -2х² + 3х + 5 = 0

Домножим на -1, чтобы избавиться от минуса перед иксом

2х² - 3х - 5 = 0

Решаем через дискриминант:

x = 1

x =  5/2

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Дана квадратичная функция f(x)=x^+2.найдите значения: 1)f(4); 2)f(-3); 3)f(-1\2); 4)f(-0.2)^.решите
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