смотрите решение на
1) f(x) " =((4x)^3 -(3x)^2) " =3*4x^(3-1)-2 *3x^(2-1) =12x^2 - 6x
3) g(x) " =(2x-1) "=2-0=2
6) g(x) " =(-3x+1)^4 " = 4(-3x+1)^(4-1) (-3x+1) " = -3*4(-3x+1)^3 = -12(-3x+1)^3
2
1) f(x) " = (sin4x-cos2x) " = cos4x (4x) " ) (2x) " = 4cos4x + 2sin2x
2) g(x) " = (cos^2 2x) " = 2cos2x (2x) " = 2*2cos2x = 4cos2x
3) f(x) " =(sin3x+cos5x) " = cos3x (3x) " + (-sin5x)(5x) ' = 3cos3x - 5sin5x
4) g(x) " =(sin^2 2x) " = 2sin2x (2x) " = 2*2sin2x = 4sin2x
Поделитесь своими знаниями, ответьте на вопрос:
Выражение 6а^6-3а^2(2а^4+а)
=6а^6-6a^6-3a^3= -3a^3