В треугольнике AMP <A=30°, <M=70°<P=80°. Какая ищ сторон треугольников наибольшая !!​

Объяснение:

б=6

а²=1²+2²=5

а=√5

тг= а/б

тг=√5/6

tg(A)= a /b

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