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Представьте в виде многочлена:а) (9а³+8b²)(8b²-9a³)б) (a³+3a²)²в) (x-3y)²(3y+x)²​

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Ответы

dmitriyb1
а) \displaystyle \tt (9a^3+8b^2)(8b^2-9a^3)=(8b^2+9a^3)(8b^2-9a^3)=\bold{64b^4-81a^6}б) \displaystyle \tt (a^3+3a^3)^2=(a^3)^2+2a^3\cdot3a^2+(3a^2)^2=\bold{a^6+6a^5+9a^4}в) \displaystyle \tt (x-3y)^2(3y+x)^2=((x-3y)(3y+x))^2=(x^2-9y^2)^2=\bold{x^4-18x^2y^2+81y^4}
badalovao256

Объяснение:

а) (9а³+8b²)(8b²-9a³)=а) (8b²+9а³+)(8b²-9a³)=(8b²)²-(9a³)²=64b^4-81a^6;

б) (a³+3a²)²=(a³)²+2× a³×3a²+(3a²)²=а^6+6a^5+9a^4;

в) (x-3y)²(3y+x)²​=((x-3y)(x+3y))²=(x²-9y²)²=(x²)²-2×x²×9y²+(9y²)²=x^4-18x²y²+81y^4;

Lusiarko65

1.Решите:

А) (а-5)(а-3) = a² - 3a - 5a + 15 = a² - 8a + 15

Б) (5х+4)(2х-1) = 10x² - 5x + 8x - 4 = 10x² + 3x - 4

В) (3р+2с)(2р+4с) = 6p² + 12pc + 4cp + 8c² = 6p² + 16pc + 8c²

Г) (b-2)(b²+2b-3) = b³ + 2b² - 3b - 2b² - 4b + 6 = b³ - 7b + 6

2. Рaзложите на множители:

А) х(х-у)+а(х-у) = (x-y)(x+a)

3. Упростите:

0,5х(4х⁴-1)(5х²+2) = (2x^5 - 0,5x)(5x² + 2) = 10x^7 + 4x^5 - 2,5x³ - x

4. Представьте многочлены в виде произведения:

А) 2а-ас-2с+с² = a(2 - c) - c(2 - c) = (a-c)(2-c)

B) bx+by-x-y-ax-ay = b(x + y) - (x + y) - a(x + y) = (x+y)(b-1-a)

arina2403423

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