Ab=7см разделите на 5 равных частей

7:5=1,4см
это равные части . проверка:
1,4•5=7см

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Задача: В равнобедренном треугольнике ABC поведена высота BD к основанию AC. Длина высоты 8,5 см, длина боковой стороны — 17 см. Определить углы этого треугольника.  

AD = DC = 17/2 = 8,5

BD = AD = DC = 8,5 ⇒ ΔABD = ΔCBD — равнобедренные, прямоугольные, ∡BDA = ∡BDC = 90°

∡DAB = ∡DBA = ∡DCB = ∡DBC = 90/2 = 45°

∡ABC = ∡DBA + ∡DBC = 45+45 = 90°

ответ: ∡BAC = 45°,

          ∡BCA = 45°,

          ∡ABC = 90°.

Задача: В равнобедренном треугольнике ABC величина угла вершины ∡B = 30°. Определить угол основания AC с высотой AM, проведенной к стороне BC. ∡MAC - ?

Р-м ΔABC — равнобедренный.

∡A = ∡C = (180−∡B)/2 = (180−30)/2 = 75°.

Р-м ΔACM — прямоугольный

∡AMC = 90°, ∡ACM = ∡C = 75°. Исходя из теоремы о сумме углов треугольника, градусная мера угла ∡MAC будет равна:

∡MAC = 180−(∡AMC+∡ACM) = 180−(90+75) = 180−165 = 15°

ответ: ∡MAC = 15°.